- ( 1+x )n = 1+nx+[n( n-1)/2!] .x2 + [n(n-1)(n-2)/3!].x3 +……
- ( 1+x )-n = 1-nx+[-n( n+1)/2!] .x2 – [n(n+1)(n+2)/3!].x3 +……
If x<<1 then x2,x3,…. is negligible. so:
- (1+x ) -n ≈ 1-nx
- (1-x ) n ≈ 1-nx
- (1-x ) -n ≈ 1+nx
If x<<1 then x2,x3,…. is negligible. so: