Impulse is given by,

$$ \vec{I} = \vec{F_a} t$$

Where \( \vec{F_a}\) is the average force acts on the particles and t is the time for which the force acts on the particle.

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# Tag: Laws of motion

## Impulse

## Force

## Learn some extra:

### What is the value of 1N in terms of fundamental units?

### What is the value of 1dyne in terms of cgs units?

### What is the relation between newton and dyne?

## Linear momentum

## Galileo’s law of inertia

Impulse is given by,

$$ \vec{I} = \vec{F_a} t$$

Where \( \vec{F_a}\) is the average force acts on the particles and t is the time for which the force acts on the particle.

Force on a particle having mass m is given by,

$$\vec{F} = m\vec{a}$$

Where, \(\vec{a}\) is the acceleration of the particle.

- SI unit of force is Newton ( N ), which is equal to kilogram metre per second ( kg m s
^{-1}).

CGS unit of force is dyne.

As we know that,

F = ma

So, 1N = 1 kg × 1m s^{-2}

Or, 1N = 1 kg m s^{-2}

So, the value of 1N in terms of fundamental units is 1 kg m s^{-2}.

As we know that,

F = ma

So, 1dyne = 1 g × 1cm s^{-2}

Or, 1dyne = 1 g cm s^{-2}

So, the value of 1dyne in terms of cgs units is 1 g cm s^{-2}.

As we know that,

F = ma

So, 1N = 1 kg × 1m s^{-2}

Or, 1N = 10^{3}g × 10^{2}cm s^{-2}

Or, 1N = 10^{5} g cm s^{-2}

Or, 1N = 10^{5} dyne

So, the 1N is equal to 10^{5} dyne.

Linear momentum of a moving particle is given by,

$$ \vec{p} = m\vec{v}$$

Where m is the mass of moving particle with velocity \( \vec{v}\)

A body continues in its state of rest or constant velocity along the same straight line, unless not disturbed by some external force. This is Galileo’s law of inertia.